i(k1 OP k2) ROUND 2 (ko)
The definitive solution:
i(v1 OP v2 OP ... OP vN)
after the optimization
i(v1) OP i(v2) .. i(vN)
For example:
i(gkd * .5 + gke)
after the opt becomes
i(gkd) * .5 + i(gke)
It's simple and I think that it's the way. I try to write the fix.
If there are objections, I annul the ko and grant the defeat to
the points.
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